Physics Problems is an excellent online study resource for students. It is an exhaustive collection of solved examples and answers for physics problems and questions.

Students can get online tutors who can help them understand the concepts and the logic behind the answers for **Physics Questions**. They can also get help with their homework problems in physics and other assignment questions related to Physics. The online physics tutors are expert in their subjects who can help the studentsÂ in solving all their queries. One can also get physics homework help from our tutors.

Physics problems cover all the important topics under physics for various grades. The students can get grade-specific help with their physics problems. The students can learn by observing the solved examples. They can understand the concepts step by step, therefore, they would be able to solve physics problems on their own. They can even learn about the topics in depth and practice problems on physics which in turn will help them to prepare for their exams.

Physics questions and answers are an entire list of solved problems and questions about physics concepts. The students can get the list of frequently asked questions of various physics topics. The following are some physics topics which are covered under the physics problems:

Here are some physics classroom examples for students:

Initial Velocity of the car = u = 18 kmph = 5 ms

Final Velocity of the car = v = 0,

Distance travelled = S = 0.5 km = 500m

We have, v

0 = 5

= 25 + 1000a.

-25 = 1000a,

a = -0.025 ms

$\therefore$ Retardation of the car = 0.025ms

T

T

Efficiency $\eta$ = 1 - $\frac{T_{2}}{T_{1}}$

= 1 - $\frac{500}{900}$

= 0.46.

Hence the efficiency of the engine is 46%.

Students can learn how to solve physics problems based on the methodology followed and illustrated in solved examples. They can get difficult physics problems solved online with our expert tutors with complete explanation of various topics. The Sample problems for motion, momentum, energy, heat, and thermodynamics have been covered.

Speed of the car for first 10 minute i.e., $\frac{1}{6}$ hour is u

Distance traveled in this time interval is S

= 5 km.

Speed of the car for the next 20 minute i.e., $\frac{1}{3}$ hour is u

Distance traveled in this time interval is S

= 20 km.

Speed of the car for the next 30 minute i.e., $\frac{1}{2}$ hour is u

Distance traveled in this time interval is S

= 20 km

Total distance traveled is given by S = S

= 5 + 20 + 20

= 45km.

Total time taken is given by: t = t

= $\frac{1}{6}$ + $\frac{1}{3}$ + $\frac{1}{2}$

= $\frac{1 + 2 + 3}{6}$ = 1hr

Average speed for the complete motion is,$\bar{v}$ = $\frac{s}{t}$

= $\frac{45}{1}$

= 45 kmph.

(i) Mass

(ii) Momentum of the body at the end of 1s?

Given:

F = 100 N,

t = 5 s,

u = 0,

v = 20 ms

Then v = u + at

Acceleration(a) = $\frac{v-u}{t}$

= $\frac{(20 - 0) ms^{-1}}{5 s}$

= 4 ms

Mass(m) = $\frac{F}{a}$

= $\frac{100 N}{4 ms^{-2}}$

= 25kg.

At the end of 5s, v = 20 ms

$\therefore$ Momentum p = mv

p = 25kg $\times$ 20 ms

p = 500 kg ms

Assume $\sigma$ = 5.7 $\times$ 10

Energy radiated per second per unit area = $\sigma$ T

$\therefore$ E = $\sigma$ T

T = 2000 K,

t = 3600s

E = 5.7 $\times$ 10

E = 0.33 $\times 10^{10}$ J.

TutorVista provides Solved Problems as well as Practice Problems for both lower Grade and higher Grade students which will help them solve problems at school easily. The online tutoring sessions offers students the opportunity to acquire a deep conceptual understanding of fundamental physics.

Some solved problems are given below:

According to the formula of speed,

We know that Speed = $\frac{Distance}{time}$

= $\frac{60}{20}$

= 3 m/s.

Given: Current, I = 0.4 A,

Time, t = 2hours

t = 2 $\times$ 60 $\times$ 60 = 7200 seconds

Q = ?

Amount of charge, Q = It

= 0.4 $\times$ 7200

= 2.88 $\times$ 10

TutorVista provides Practice Problems for students to improve their skills and ability to check their intellectual level. This will help them speed up their potential and also perform well in their tests. Since your goal should be to become familiar with basic meanings of concepts in order to solve problems with ease.

Some solved practice problems are mentioned below:

Given, Radius of earth R = 6.37 $\times$ 10

Mass of earth M = 5.98 $\times$ 10

Gravitational constant G = 6.67300 $\times$ 10

Equation of force,

F = $\frac{GMm}{R^{2}}$

where F is the force,

m is the mass of the body,

g is the acceleration due to gravity,

M is the mass of the Earth,

R is the radius of the Earth and

G is the gravitational constant

F = $\frac{GMm}{r^{2}}$ = m $\times$ a.

The acceleration due to gravity is given by

a = $\frac{GM}{r^{2}}$

= $\frac{6.67300 Ă— 10^{-11} m^{3} kg^{-1} s^{-2} \times 5.98 \times 10^{24} kg}{6.37 \times 10^{3} m}^{2}$.

= 9.8 m/s

Current drawn I = 5 A

$\therefore$ Power rating P = V $\times$ I

= 220 $\times$ 5

= 1100 W.

Thus the Power rating is 1100 W.

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