Newton's first law explains what happens to an object when no force acts on it, it either remains at rest or moves in a straight line with constant speed.

Newtons Second Law answers the question of what happens to an object when one or more forces act on it.

Newtons Second Law answers the question of what happens to an object when one or more forces act on it.

Consider that there is a block which is lying on the floor. If force of F
N is applied to the block, the block will surpass the force of friction
between the block and the surface and start moving with the acceleration
"a".

In the second case the force applied doubles or we can say
that force of 2F N is applied to the block then the acceleration of the
block will also doubles and becomes "2a". If we make the force 3F the
acceleration will become "3a" and so on.

Now we will explain the
relationship between mass and acceleration first.** ****Mass of an object
shows how much inertia is contained in the object.** If the mass of
object is more, lesser would be its acceleration under the same applied
force F. For example, if force F produces an acceleration of 6 m/sec^{2} in an object having mass m, then acceleration of the object will be halved equal to 3 m/sec^{2}; the mass of the object is doubled and if the same force F Newton is applied to the object.

To formulate the mass and calculate it quantitatively, if same force F Newton is applied to the two objects having mass m_{1} and m_{2} and having accelerations a_{1} and a_{2} respectively,

Relation between the applied force and the acceleration is already explained. Now,
we will discuss the relationship between the acceleration and the mass
further. From above discussion we can conclude that the acceleration
magnitudes are inversely proportional to the ratio of their masses.

$\frac{m_{2}}{m_{1}}$=$\frac{a_{1}}{a_{2}}$

This results in
Newtons Second Law.

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"Acceleration of the objects is directly proportional to the net or resultant force acting on it and inversely proportional to the mass of the object. "

When force F is applied to the object. Suppose that force F is applied to the object and this result in change in the velocity of the object from its initial velocity v1 at the time interval t1, to the velocity v2 at time interval t2.

If we consider that the mass of the object remains same then,

F = m $\frac{dv}{dt}$

F = m $\frac{v_{2} - v_{1}}{t_{2} - t_{1}}$

If mass of the object also changes when force F is applied to the object then,

**F = $\frac{(m_{2}v_{2}- m_{1}v_{1})} {(t_{2}-t_{1})}$**

Every object on earth is attracted towards the earth. This force which is exerted on the object by the earth is called as the gravity force (F

There is a difference between the mass and the weight of the object.

Freely falling object towards the earth experiences an acceleration of 'g' towards the center of the earth and if the mass of the object is m, then the weight of the object is equal to

$F_{g} = mg$

Where, g = 9.8 m/sec

If one weight of 8 Newton and another weight of 2 Newton is thrown above with the same applied force. Then
the 2 Newton weight will travel at higher speed and has more
acceleration than the 2 Newton weight with the same amount of force, as
the mass of 2N weigh is less.

- As the weight of the object depends on the value of acceleration g, weight of the object varies as the geographic location changes.
- As the object moves away from the center of the earth the value of 'g' decreases and its weight decreases.
- Another example is that value of 'g' on the moon is 1/6
^{th}of the value on the earth.

Here, mass of both the pieces of rock is same, to produce the acceleration of 10a , force applied would be equal to

F

= 10F

Therefore, 10 times of the force applied to the first rock needs to be applied to the second rock to produce an acceleration of 10a.

Here, we need to find the acceleration of the object, so we will apply the Newton’s second law which can be stated as the

F = ma

Newton’s second law of motion:

10 = 2a

a = $\frac{10}{2}$

a = 5 m/sec^{2}

Now here the resultant force acting on the object is

$F_{1}$ - $F_{2}$ = 10 - 4 = 6N

Resultant force = ($m_{2}$ - $m_{1}$) a

Therefore,

a = $\frac{6}{2}$

a = 3 m / sec^{2}

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