The word **kinetic** originated from the Greek word* ***"****kinesis**"* *which means motion. Kinetic energy is basically the energy of motion.

Any object, which is in the state of motion, whether in a horizontal or vertical direction will possess some kinetic energy.

**The Energy possessed by an object by virtue of its motion.**

Any object, which is in the state of motion, whether in a horizontal or vertical direction will possess some kinetic energy.

So, kinetic energy is a form of energy that represents motion. Kinetic energy has magnitude. It has no direction.

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Let us start with the constant acceleration equation:

$V_{f}^{2} - V_{i}^{2}$ = $2ad$

Replace $a$ = $\frac{F}{m}$

$V_{f}^{2} - V_{i}^{2}$ = $\frac{2Fd}{m}$

If $V_{i}$ = 0 and work is force through distance then

W = E = $\frac{1}{2}$$mv^{2}$

Another way:

$\Delta K = W$ =$\int F(r) dr$= $\int madr$ = $m\int$ $\frac{dv}{dt}$$dr$

Evaluating the integral:

$\Delta K$ = $m\int$ $\frac{dv}{dt}$$dr$ = $m\int$ $\frac{dr}{dt}$$dv$ = $m\int vdv$

Kinetic energy K.E. = $\frac{1}{2}$$mv^{2}$

Hence kinetic energy unit = **$\frac{1}{2}$** kg (m/sec^{2})

1 joule = 1 kg(m / sec^{2})

The average kinetic energy is also called as temperature. You must be thinking that both have different units, i.e., temperature being measured in kelvins and energy in Joules. This is true but both of these are related to each other.

If we increase the temperature of the gas, the molecules will have more internal energy and hence the average kinetic energy would be more. If we talk about the average kinetic energy then temperature is the direct measure of it.

$T$ = $\frac{2}{3k_{b}}$($\frac{1}{2}$$mv^{2}$) [average]

Hence average kinetic energy of molecules = $\frac{1}{2}$$mv_{aver}^{2}$ = $\frac{3}{2}$ $K_{b}T$

Translational motion is the motion along a line or in the space. So, the kinetic energy possessed by the body or the object on account of its translational motion is called translational kinetic energy.

$E$ = $\frac{1}{2}$$mv^{2}$

Derivation:

We know: $work$= $F.dx$ = $F.Vdt$

$dF\times vdt$ = $v.d(mv)$

Now $E_{k}$= $\int F.dx$ = $\int v.d(mv)$ = $\int d$($\frac{mv^{2}}{2}$) = $\frac{1}{2}mv^{2}$ When we talk about eddies during a turbulent flow then the energy related to a unit mass of it is called turbulent kinetic energy.

It is given by:

$K$ = $\frac{1}{2}$$(u_{1}^{2} + u_{2}^{2}+u_{3}^{2})$

Here u = turbulence normal stress If the body’s speed is close to the fraction of the speed of light or 'c' then it is necessary to use the concept of relativistic kinetic energy.To calculate it we use the concept of relative mechanics.

We know that, $E_{k}$= $\int vdP$

= $\int v d(myv)$ [as P = m y c]

=$myv^{2}$ - $\frac{m}{2}$ $\int yd(v^{2})$

Solving and taking E

Also $E_{0} = mc^{2}$

So $E_{k} = myc^{2}-mc^{2}$

Here $y$=$\sqrt{1 –\frac{v^{2}}{c^{2}}}-1$ Negative kinetic energy is not possible if we consider the macroscopic objects because negative kinetic energy would mean that either the mass is negative, which is not possible or the velocity is negative. Both these are not feasible.

But the concept of negative kinetic energy comes from the

Solving the Schrodinger Equations for tunneling we can mathematically calculate the negative kinetic energy.

Kinetic energy can never become negative. But we can see that the change in kinetic energy or delta can be negative.

For example, if we throw the ball in the sky then at the peak point the kinetic energy becomes zero and now the change would be negative.

Tunneling is a process in which the particle will travel by an imaginary route made by itself and not by the usual route. Tunneling has been proved and observed experimentally. So, this is all about the negative kinetic energy. Understanding will improve once you understand the basics of quantum mechanics.

Translational kinetic energy = $\frac{1}{2}$$mv^{2}$

Rotational kinetic energy = $\frac{1}{2}$$Iw^{2}$

Hence, Total KInetic Energy $E_{k}$ = $\frac{1}{2}$$mv^{2}$ + $\frac{1}{2}$$Iw^{2}$

Here I = moment of inertia, w = angular velocity, v = translational velocity, m = mass of the body or the object.

Example a rolling ball will have both kind of kinetic energy, translational as well as rotational.

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