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Physics answers is an excellent online study resource for students. It is an exhaustive collection of solved examples and answers for physics problems and questions. Mastering physics becomes possible with online practice of the problems with our qualified tutors.

Students can get online tutors who can help them understand the concepts and the logic behind the answers for physics questions. They can also get help with their homework problems and other assignment questions related to the subject. The online physics tutors are expert in their subjects who can help the students with all their queries.

The students can get grade-specific help to find answers for all of their physics problems. The students can learn by observing the solved examples. They can understand the concepts step by step, and therefore, they would be able to solve physics problems on their own. They can learn about the topics in depth and practice problems in order to prepare for their examinations.

Mastering physics, as the name suggests, helps students to master answering physics problems and physics questions. They can avail the free physics help available online to understand various concepts and to learn from the solved examples. They can get elaborate explanations on specific topics with practice tests on them so that they can test their learning and practice well for their examinations.

Students can get answers to Physics questions online. There are sets of solved questions which have answers explained step by step.
The following units are covered :

• Motions and Forces
• Conservation of Energy and Momentum
• Heat and Thermodynamics
• Waves
• Electric and Magnetic Phenomena.

The topics are divided into Physics I, II, III and IV based on the complexity of the topics involved. The topics have also been divided on the basis of grades. Hence students can get grade specific help. They can also get help with their homework problems.

Physics Experts

Students can avail the Physics help from the online tutors. The students can avail the excellent service. They can have a demo session with the tutors. The tutors are experts in their subjects who can provide excellent support with the concepts to the students. They can also get help with understanding the diagrams and the steps of computation. They can get the online help 24 $\times$ 7.

Students can get answers in any physics topics from this website which is arranged in an order. If they are still having any queries they can have online sessions with tutors.

Solved Examples

Question 1: A Constant retarding force of 100 N is acting on a body of mass 20 kg moving initially with a speed of 15m/s. How long does the body take to stop?
Solution:

Retarding force F = 100N or
Force F = -100N,
mass m = 20 kg,
Initial Velocity (u) = 15 m/s,
Final Veloctiy (V) = 0
From Newtons Second Law, F = ma
-100N = 20Kg $\times$ a
Acceleration (a) = $\frac{-100 N}{20 kg}$
= - 5m/s2.
But we also know that a = $\frac{V-U}{t}$
-5 = $\frac{0-15}{t}$
-5t = -15
t = 3s.
Time required to stop the body = 3s.

Question 2: What is the magnitude of the force which when it acts on a mass of 10 kg gives it a velocity of 5m/s in one minute?
Solution:

From Newtons second law, F=ma
Initial Velocity (u) = 0,
Final Velocity (V) = 5m/s,
Time (t) = 1 min = 60 s.
$\therefore$ Acceleration = a = $\frac{V-U}{t}$
= $\frac{5-0}{60}$
= $\frac{1}{12}$ m/s2.

Force = ma = 10 $\times$ $\frac{1}{12}$
= $\frac{10}{12}$
= 0.833 N.

The Physics answers are mentioned as per the curriculum. The Concepts are dealt in depth so that the students can gain maximum benefit out of that. The diagrams, tabular column, equations and all are represented in a systematic way to know about any topic in a better way.

Solved Examples

Question 1: What will be the change in the acceleration, if the mass is doubled while constant force is acting on it?
Solution:

From Newtons Second law, F = ma.
Let force acting on the object when the mass is doubled be equal to F1.
i.e., Mass(m1) = 2m
Acceleration produced = a1

F1 = 2m $\times$ a1
given F = F1
$\therefore$ ma = 2 ma1
a = 2a1
Acceleration, a1 = $\frac{a}{2}$.
Thus, acceleration is reduced to half of the given acceleration if mass is doubled.

Question 2: Explain the following:
(a) State two characteristics of wave motion.
(b) What is the relation between frequency, wavelength and speed of a wave?
Solution:

(a)A wave motion is periodic in nature.The particles of the medium do not move from their mean position but execute vibration but only the energy is transmitted from one point to another.

(b) v = $\lambda$ $\times$ f
where V = Velocity,
$\lambda$ = wavelength,
f = frequency.

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