Here we discuss the property of moving object which is called momentum. This term means moving mass. This is the property which possesses in moving object due to its movement or motion and mass. This is a physics term. It can also be defined as the motion quantity of object; for example, a moving sports team has the momentum or if an object is moving then it contains momentum.

As we know all objects have some amount of mass, so when they get move or in motion condition then these possess momentum. So it consists mass in motions. It depends only on two main factors that are**mass and velocity of moving object**. Or two main variables are the speed of moving object and it mass. The system’s momentum is the vector sum quantity of the object’s momenta which forms the system. In case of an isolated system, then the system’s momentum is a constant for motion and follows the principle of conservation of momentum. Here we discuss all about momentum, its mathematical representation, its variable factors, and its different types.

As we know all objects have some amount of mass, so when they get move or in motion condition then these possess momentum. So it consists mass in motions. It depends only on two main factors that are

These are certain points which describes the basics of momentum:

**the Newton's Law of Motion**:

All moving bodies will continue to be in the state of rest or motion unless interfered by some external force. The same law applies to momentum as well. That is, if the mass and velocity of an object remain the same then the momentum of the object remains constant, i.e.,** mv** = Constant.

- It is a vector quantity and has got same direction as that of Velocity.
- It is the product of object's mass and its velocity (moving object).
- The greater the mass or weight the greater is the momentum.
- It is an indication of how tough or difficult it would be to stop a moving object.

All moving bodies will continue to be in the state of rest or motion unless interfered by some external force. The same law applies to momentum as well. That is, if the mass and velocity of an object remain the same then the momentum of the object remains constant, i.e.,

Figure: Depicting the relation of momentum with mass and velocity

Momentum is a property of the body possessed by virtue of its mass and velocity. It is the product of mass of the body and its velocity.

**Momentum = mass $\times$ velocity**

p = m $\times$ v

S.I Unit of momentum = kgms^{-1}It is important to note that for a body in motion, the momentum is zero as the velocity is zero.

When the object moves then it gains momentum as the velocity increases. Hence greater the velocity greater is the momentum.

For Example: It is evident from the fact that it is difficult to stop a truck than a bicycle because of the momentum difference. It can also be visualized from the fact that a truck involved in an accident will do more harm than any bicycle.

The quantity of motion of the body or an object is measured by momentum. It can also be called as “**The impulse of the moving object**”. It should be noted that momentum is a conserved quantity.

p = m $\times$ v

When the object moves then it gains momentum as the velocity increases. Hence greater the velocity greater is the momentum.

For Example:

The quantity of motion of the body or an object is measured by momentum. It can also be called as “

Hence sigma F = $\frac{d p}{d t}$

= $\left \{ \frac{(m)dv}{dt} \right \}+\left \{\frac{(v)dm}{dt} \right \}$

[ As the mass is constant and does not change hence $\frac{(v)dm}{dt}$ = 0 ]

Hence F = m a

Here

The basic formula for momentum of the moving body is:

**P = mv ....................(1)**

Where,

p = momentum of the body

m = mass

v = velocity of the moving body

**Units: **

The unit of mass in S.I. system is**Kg** and

The unit of velocity in S.I. system is**m/s**

so, the unit of momentum is**kgm/s**

Also, if velocity is expressed as change of velocity then the formula becomes:

**P = m(v**_{1} - v_{2})...................(2)

Where,

v_{1} is the final velocity and

v_{2} is the initial velocity

For a system of particles the formula changes to:

**P = $\sigma$ m v**

= m_{1} v_{1} + m_{2} v_{2} + m_{3} v_{3} + m_{4} v_{4} + . . . . . . . . . . . . .+ m_{i} v_{i }................(3)

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p = momentum of the body

m = mass

v = velocity of the moving body

The unit of mass in S.I. system is

The unit of velocity in S.I. system is

so, the unit of momentum is

Also, if velocity is expressed as change of velocity then the formula becomes:

v

v

For a system of particles the formula changes to:

= m

According to the formula of momentum P = m v, the SI unit is **Kgm/s**. Also expressed in **N-s** or **Newton second**.

Let us suppose the file cabinet is in the middle of the room, a room with a smooth floor, we give it a push in order to move it close to the wall and before we realize, it slams into the wall. It is difficult to stop because it has linear momentum. **The measure of an object’s or body’s translation motion is called Linear Momentum.**_{x}, P_{y},P_{z} etc.

Here,

_{x}, V_{y}, V_{z }are the velocities in x, y and z directions respectively.

**Linear momentum is dependent on the frame of reference: **

It is important to note that the an object can have momentum for one frame of reference but the same object if kept in another reference frame can have zero momentum.

Lets us take an example:

An airplane has a velocity of 20 km/s and mass of 100 kg, then the momentum taking the earth as frame of reference is 20 $\times$ 100 = 2000 Kg Km/s. But to the pilot in the cockpit it has a velocity and momentum of zero.

Linear momentum of a system of particles: for a system of particles with a mass of m_{1}, m_{2}, m_{3} and so on and a velocity v_{1}, v_{2}, v_{3} and so on the linear momentum can be expressed as:

P = $\sigma$ m v

= m_{1} v_{1} + m_{2} v_{2} + m_{3} v_{3} + m_{4} v_{4} + . . . . . . . . . . . . .+ m_{i} v_{i} .................(a)

- Linear momentum is a vector quantity.
- The direction of linear momentum is in the direction of velocity of the object.
- The formula for linear momentum remains the same, p = m v.

Here,

P_{x} = m V_{x}

P_{y} = m V_{y}

P_{z} = m V_{z}

Where VP

P

Lets us take an example:

An airplane has a velocity of 20 km/s and mass of 100 kg, then the momentum taking the earth as frame of reference is 20 $\times$ 100 = 2000 Kg Km/s. But to the pilot in the cockpit it has a velocity and momentum of zero.

Linear momentum of a system of particles:

P = $\sigma$ m v

= m

We know that,

P = m v

If we consider the velocity to be the initial and final velocity represented by u and v then momentum change or

The change in momentum would be expressed as:

P = m (v – u)

**P = mv – mu**

**mv** is the **Final Momentum** and

mu is the **Initial Momentum**

The change in momentum is also called as**Impulse**.

P = m v

If we consider the velocity to be the initial and final velocity represented by u and v then momentum change or

The change in momentum would be expressed as:

P = m (v – u)

$\Delta P$ = m $\Delta$ vHence, the change in momentum is equal to mass times the change in velocity.

Here mu

The change in momentum is also called as

The momentum defined and used in relativistic mechanics is called **Relativistic Momentum**. In relativistic mechanics the momentum is defined as follows:

**P = y mo v . . . . . . . . . . . . . . . . . . . (1)**

Here y is the Lorentz factor.

It is equal to,

**y = $\frac{1}{\sqrt{1-\frac{v^{2}}{c^{2}}}}$**

Here,

v is the object's speed

c is the light's speed

m_{o} is the invariant mass

Also the inverse relation can be expressed as:

The total energy E of any body is also related to relativistic momentum as:

**E**^{2 }= (P c)^{2} + ( m_{0} c^{2})^{2} .......................(1)

Where, P = magnitude of momentum

For mass less particles m_{0} = 0

Hence E = p c

Figure: Depicting the concept of relativistic momentum

It is equal to,

v is the object's speed

c is the light's speed

m

Also the inverse relation can be expressed as:

v = $\frac{c^{2}P}{\sqrt{(pc)^{2} + (m_{0}c^{2})^{2}}}$

Where P = $\sqrt{(P^{2}x + P^{2}y + P^{2}z)}$ The total energy E of any body is also related to relativistic momentum as:

For mass less particles m

Hence E = p c

Figure: Depicting the concept of relativistic momentum

The change of momentum is also termed as impulse. It is denoted by “I “.

Hence I = $\Delta$ P

$\frac{dp}{dt}$ = $\frac{d(mv)}{dt}$.

$\frac{dp}{dt}$ = m$\frac{dv}{dt}$ = ma

$\frac{dp}{dt}$ = F

Hence the above equations can be written as: dp = Fdt

So,

$\Delta$ P = F $\Delta$ T = P_{(final)} – P_{(initial)} ............................(1)and

**I = $\Delta$ P = change in momentum ...........................(2)**The S.I. unit of Impulse is **Ns**.

According to the law of conservation of momentum the momentum of the closed system of objects remains conserved given the fact no external force acts on it.Hence I = $\Delta$ P

$\frac{dp}{dt}$ = $\frac{d(mv)}{dt}$.

$\frac{dp}{dt}$ = m$\frac{dv}{dt}$ = ma

$\frac{dp}{dt}$ = F

Hence the above equations can be written as: dp = Fdt

So,

$\Delta$ P = F $\Delta$ T = P

or

if no external force acts on a system in a particular direction then the total momentum of the system in the direction remains unchanged.

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There can be many types of momentum problems. They can be based on the calculations of momentum, impulse, force etc.

The steps to be followed to solve the basic problems of momentum:

The steps to be followed to solve the basic problems of momentum:

- If simply momentum has to be calculated than calculate the initial and final velocities using the equations of motion.
- Calculate the momentum by multiplying mass with velocities.
- In order to calculate the Impulse calculate the force integrating it over time t
_{1}and t_{2}.

Below are given some numericals which helps us to understand more of momentum:

Given: mass m = 1kg,

Velocity v = 10 m/s.

Momentum p is given by: p = mv

= (1 kg) $\times$ (10m/s)

= 10 kg m/s.

Find: (a) Initial momentum

(b) Final momentum

(c) Change in momentum

(d) Impulse

(e) Calculate its magnitude if force acts for 1 s?

Given mass m = 3kg,

Initial Velocity V

Final Velocity V

(a) Initial momentum, pi = mv

(b) Final momentum, pf = mv

(c) Change in momentum, $\Delta$ p = p

(d) Impulse, J = Ft = $\Delta$ p

= 24Ns.

(e)Magnitude of force is given by: F = $\frac{J}{t}$

= $\frac{24 Ns}{1 s}$

= 24N.

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